Question

For the arrangement shown in figure the coefficient of friction between the two blocks is m. If both the block are identical, then the acceleration of each block is-

• A. $\frac { F } { 2 m }$ – 2mg
• B. $\frac { F } { 2 m }$
• C. $\frac { F } { 2 m }$ – mg
• D. Zero

Answer 1

Answer: (C)

$\frac { F } { 2 m }$ – mg

Answer 2

In fig, direction of friction is shown,

F – T – µmg = ma

T – µmg = ma

Solving the equations, a = $\frac { F - 2 \mu \mathrm { mg } } { 2 \mathrm {~m} }$