Question
Physics Question on Oscillations
For Simple Harmonic Oscillator, the potential energy is equal to kinetic energy
A
twice during each cycle
B
four times during each cycle
C
when x=0
D
when x=a
Answer
four times during each cycle
Explanation
Solution
Total energy = PE+KE . When a particle executes SHM, there is one position between maximum amplitude and mean position where PE is equal to KE , and particle have to cross that point four times to complete one oscillation.