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Question

Physics Question on Oscillations

For Simple Harmonic Oscillator, the potential energy is equal to kinetic energy

A

twice during each cycle

B

four times during each cycle

C

when x=0x=0

D

when x=ax=a

Answer

four times during each cycle

Explanation

Solution

Total energy = PE+KEP \, E \, + \, K \, E . When a particle executes SHM, there is one position between maximum amplitude and mean position where PEPE is equal to KEKE , and particle have to cross that point four times to complete one oscillation.