Question

For silver, ${C_{p}(JK^{-1} mol^{-1}) = 23 + 0.01T}$. If the temperature (T) of $3$ moles of silver is raised from $300\,K$ to $1000\, K$ at $1\, atm$ pressure, the value of $\Delta H$ will be close to

• A. 21 kJ
• B. 16 kJ
• C. 13 kJ
• D. 62 kJ

Answer 1

Answer: (D)

62 kJ

Answer 2

$\Delta H =n \int^{T_{2}}_{T_1} C_{p,m} dT = 3 \times\int^{1000}_{300} \left(23+0.01T\right)dT$ $= 3\left[23\left(1000-300\right)+ \frac{0.01}{2} \left(1000^{2} - 300^{2}\right)\right]$ $= 61950 J \approx 2 kJ$