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Question

Chemistry Question on Thermodynamics

For reversible process, the value of ΔS\Delta S is gives by the expression:

A

q(rev)×T{{q}_{(rev)}}\times T

B

q(rev)÷T{{q}_{(rev)}}\div T

C

ΔH/ΔT\Delta H/\Delta T

D

T÷q(rev)T\div {{q}_{(rev)}}

Answer

q(rev)÷T{{q}_{(rev)}}\div T

Explanation

Solution

Entropy (S) is the measurement of disorder of the molecules or randomness. It is an extension property & is a stable function. The change in entropy during a process is mathematically given as: ΔrS0=S0(\Delta_{ r } S ^{0}=\sum S ^{0}( products )S0()-\sum S ^{0}( reactants )) =qrevT=ΔHT=\frac{ q _{ rev }}{ T }=\frac{\Delta H }{ T } \therefore For reversible process, ΔS=qrevT\Delta S=\frac{q_{r e v}}{T}