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Question

Mathematics Question on Functions

For real x,x, let f(x)=x3+5x+1,f (x) = x^3 + 5x + 1, then

A

f is one-one but not onto R

B

f is onto R but not one-one

C

f is one-one and onto R

D

f is neither one-one nor onto R

Answer

f is one-one and onto R

Explanation

Solution

Given f(x)=x3+5x+1f (x) = x^3 + 5x + 1 Now f(x)=3x2+5>0,?x?Rf '\left(x\right)=3x^{2}+5 > 0, ?x ?R f(x)\therefore f \left(x\right) is strictly increasing function \therefore It is one-one Clearly, f(x)f\left(x\right) is a continuous function and also increasing on R, Ltxf(x)=Lt_{x\rightarrow-\infty}\,f \left(x\right)=-\infty and Ltxf(x)=Lt_{x\rightarrow\infty}\,f \left(x\right)=\infty f(x)\therefore f\left(x\right) takes every value between 8-8 and 88 . Thus, f(x)f\left(x\right) is onto function.