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Question: For real numbers x and y, we write x Ry ⇔\(x - y + \sqrt { 2 }\) is an irrational number. Then the r...

For real numbers x and y, we write x Ry ⇔xy+2x - y + \sqrt { 2 } is an irrational number. Then the relation R is

A

Reflexive

B

Symmetric

C

Transitive

D

None of these

Answer

Reflexive

Explanation

Solution

For any xRx \in R we have xx+2=2x - x + \sqrt { 2 } = \sqrt { 2 } an irrational number.

xRxx R x for all x. So, R is reflexive.

R is not symmetric, because 2R1\sqrt { 2 } R 1 but 1R21 R \sqrt { 2 }, R is not transitive also because 2\sqrt { 2 } R 1 and 1R221 R 2 \sqrt { 2 } but 2R22\sqrt { 2 } R 2 \sqrt { 2 } .