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Question

Chemistry Question on Equilibrium

For reaction : SO2(g)+12O2(g)=SO3(g)SO _2( g )+\frac{1}{2} O _2( g )= SO _3( g ) Kp=2×1012K _{ p }=2 \times 10^{12} at 27C27^{\circ} C and 1 atm pressure The KcK _{ c } for the same reaction is ____×1013\times 10^{13} (Nearest integer)(Given R=0.082LatmK1mol1R =0.082 \,L \,atm \,K ^{-1} \,mol ^{-1} )

Answer

The correct answer is 1.
SO2(g)​+21​O2(g)​⇌SO3(g)​
Kp​=2×1012 at 300K
Kp​=KC​×(RT)Δng​
2×1012=Kc​×(0.082×300)−1/2
KC​=9.92×1012
KC​=0.992×1013
=1