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Question: For reaction RX + OH<sup>–</sup>® ROH + X<sup>–</sup>, Rate expression is R = 4.7 × 10<sup>–5</sup>...

For reaction RX + OH–® ROH + X–, Rate expression is

R = 4.7 × 10–5 [RX][OH–] + 2.4 × 10–5 [RX].

What % of reactant react by SN2S_{N^{2}}mechanism when [OH–]

= 0.001 molar -

A

1.9

B

66.2

C

95.1

D

16.4

Answer

1.9

Explanation

Solution

Fraction of reactant decomposing

by SN2S_{N^{2}}mechanism = 4.7×10–5[RX][OH–]4.7×10–5[RX][OH–]+2.4×10–5[RX]\frac{4.7 \times 10^{–5}\lbrack RX\rbrack\lbrack OH^{–}\rbrack}{4.7 \times 10^{–5}\lbrack RX\rbrack\lbrack OH^{–}\rbrack + 2.4 \times 10^{–5}\lbrack RX\rbrack}Put [OH–] = 0.001 M