Solveeit Logo

Question

Question: For reaction $CrO_2Cl_2 + NaOH \longrightarrow B + NaCl + H_2O$ $B + H^+ \longrightarrow C + H_2O$...

For reaction

CrO2Cl2+NaOHB+NaCl+H2OCrO_2Cl_2 + NaOH \longrightarrow B + NaCl + H_2O

B+H+C+H2OB + H^+ \longrightarrow C + H_2O

Then number of terminal oxygen in C is ______

Answer

4

Explanation

Solution

The compound CrO2Cl2CrO_2Cl_2 (chromyl chloride) reacts with NaOHNaOH to form a chromate salt (B), which upon acidification gives chromic acid (C, H2CrO4H_2CrO_4). In chromic acid the chromium is tetrahedrally coordinated by four oxygen atoms, all of which are terminal.

Details:

  1. CrO2Cl2CrO_2Cl_2 (with Cr in +6 oxidation state) reacts with NaOHNaOH to yield a chromate salt.

  2. Acidifying the chromate salt converts it to chromic acid H2CrO4H_2CrO_4.

  3. In H2CrO4H_2CrO_4, the Cr atom is bonded to four oxygen atoms (all terminal).