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Question: For reaction 2NOCl(g) ⇌ <img src="https://cdn.pureessence.tech/canvas_427.png?top_left_x=764&top_lef...

For reaction 2NOCl(g) ⇌ , KCK _ { C }at 427°C is 3×10−6 L mol−13 \times 10 ^ { - 6 } \mathrm {~L} \mathrm {~mol} ^ { - 1 }. The value of KPK _ { P } is nearly.

A

7.50×10−57.50 \times 10 ^ { - 5 }

B

2.50×10−52.50 \times 10 ^ { - 5 }

C

2.50×10−42.50 \times 10 ^ { - 4 }

D

1.75×10−41.75 \times 10 ^ { - 4 }

Answer

1.75×10−41.75 \times 10 ^ { - 4 }

Explanation

Solution

2NOCl(g) = 2NO(g) + Cl2(g)

Kp = KC (RT)∆n

Kp = 3 × 10–6 (0.0821 × 700) = 172.41 × 10­–6

= 1.72 × 10–4