Solveeit Logo

Question

Question: For \(PdC{l_2}.4N{H_3}\), \(PtC{l_2}.2N{H_3}\)and \(CoC{l_3}.4N{H_3}\) reacts with excess amount of ...

For PdCl2.4NH3PdC{l_2}.4N{H_3}, PtCl2.2NH3PtC{l_2}.2N{H_3}and CoCl3.4NH3CoC{l_3}.4N{H_3} reacts with excess amount of AgNO3AgN{O_3} individually and gave 2  mole2\;mole of AgClAgCl, zero molemole of AgClAgCl, 1mole1mole of AgClAgCl respectively. Then identify the secondary valences of PdPd, PtPt and CoCorespectively.
(1)    6,4,7\left( 1 \right)\;\;6,4,7
(2)    4,2,4\left( 2 \right)\;\;4,2,4
(3)    2,2,3\left( 3 \right)\;\;2,2,3
(4)    4,4,6\left( 4 \right)\;\;4,4,6

Explanation

Solution

We are talking about coordinated compounds here so first we should learn about coordinated compounds. Coordinated compounds are chemical compounds that contain multiple anion or neutral molecules that are connected to a central metal atom through a coordinate bond. We will discuss their valency. The central metal atom has two valencies: a primary valency and secondary valency.

Complete answer:
Let us understand the given option first, PdCl2.4NH3PdC{l_2}.4N{H_3} is reacting with excess amount of AgNO3AgN{O_3} to give 2  mole2\;mole of AgClAgCl we can observe that for 2  mole2\;mole of AgClAgCl to be formed PdCl2.4NH3PdC{l_2}.4N{H_3} must have reacted with 2  mole2\;mole of AgNO3AgN{O_3} so the remaining compound will be Pd(NH3)4Pd{\left( {N{H_3}} \right)_4} it contains four coordinated molecule or ligands so its secondary valency is four.
Let’s see the second option, PtCl2.2NH3PtC{l_2}.2N{H_3} is reacting with excess amount of AgNO3AgN{O_3} to give zero moles of AgClAgCl we can observe that PtCl2.2NH3PtC{l_2}.2N{H_3} did not react and no amount of product was formed so PtCl2.2NH3PtC{l_2}.2N{H_3} remains same, as it contains four coordinated molecule or ligands so its secondary valency is four.
Let's see the third option CoCl3.4NH3CoC{l_3}.4N{H_3} is reacting with excess amount of AgNO3AgN{O_3} to give 1mole1mole of AgClAgCl we can observe that for 1mole1mole of AgClAgCl to be formed, CoCl3.4NH3CoC{l_3}.4N{H_3} must have reacted with 1mole1mole of AgNO3AgN{O_3} so one chlorine is lost and now the remaining compound is CoCl2.4NH3CoC{l_2}.4N{H_3}, as it contains six coordinated groups or ligands its secondary valency is six.
So, the correct answer is option (4)\left( 4 \right).

Note:
Secondary valency of an element in a compound is the number of ion molecules that are coordinated to the element or it can be defined as the number of ligands that are attached to the element. Coordinated groups are also known as ligands.