Question

For particle P revolving round the centre O with radius of circular path r and angular velocity ω, as shown in below figure, the projection of OP on the x-axis at time t is

• A. x(t) = rcos (ωt )
• B. x(t) = rcos (ωt - $\frac{π}{6}$ ω)
• C. x(t) = rcos (ωt + $\frac{π}{6}$)
• D. x(t) = rsin (ωt + $\frac{π}{6}$)

Answer 1

Answer: (C)

x(t) = rcos (ωt + $\frac{π}{6}$)

Answer 2

The correct option is(C): x(t) = rcos (ωt + $\frac{π}{6}$)