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Question

Chemistry Question on The solid state

For orthorhombic system axial ratios are abca \ne b \ne c and the axial angles are

A

α=β=γ90\alpha = \beta = \gamma \ne 90^\circ

B

α=β=γ=90\alpha = \beta = \gamma = 90^\circ

C

α=γ=90,β90\alpha = \gamma = 90^\circ, \beta \ne 90^\circ

D

αβγ90\alpha \ne \beta \ne \gamma \ne 90^\circ

Answer

α=β=γ=90\alpha = \beta = \gamma = 90^\circ

Explanation

Solution

Orthorhombic crystal has three unequal axis
which are at right angle to each other abc,a \ne b \ne c, all
angles = 9090^\circ
So, axial distances abc,a \ne b \ne c, and axial angles
a = p = y = 9090^\circ