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Question

Chemistry Question on Thermodynamics

For one mole of NaCl(s) {NaCl_{(s)}} the lattice enthalpy is

A

788kJ/mol-788 \,kJ/mol

B

+878kJ/mol+878 \,kJ/mol

C

+788kJ/mol+788\, kJ/mol

D

878kJ/mol-878 \,kJ/mol

Answer

788kJ/mol-788 \,kJ/mol

Explanation

Solution

Δ/H?=S+D+J.E.+E.A.+U\Delta /H? = S + D +J.E.+ E.A. + U
411.2=108.4+121+495.6348.6+U- 411.2 = 108.4 + 121 + 495.6 - 348.6 + U
U=787.6kJ/molU { = - 787.6 kJ/mol}
=788kJ/mol{= - 788 kJ/mol}