Question

For one complete cycle of a thermodynamic process on a gas as shown in the P-V diagram. Which of the following is correct ?

• A. DE_int= 0, Q < 0
• B. DE_int= 0, Q > 0
• C. DE_int> 0, Q < 0
• D. DE_int< 0, Q > 0

Answer 1

Answer: (A)

DE_int= 0, Q < 0

Answer 2

DE_int = 0, for a complete cycle and for given cycle work done is negative, so from first law of thermodynamics Q will be negative i.e. Q < 0.