Question
Question: For N<sub>2</sub>(g) + 3H<sub>2</sub>(g) ® 2NH<sub>3</sub>(g) + 22 kcal, E<sub>a</sub> for the react...
For N2(g) + 3H2(g) ® 2NH3(g) + 22 kcal, Ea for the reaction is 70 kcal. Hence, the activation energy for
2NH3(g) ® N2(g) + 3H2(g) is
A
92 kcal
B
70 kcal
C
48 kcal
D
22 kcal
Answer
92 kcal
Explanation
Solution
DH = Ef – Eb
–22 = 70 – Eb
Eb = 92 kcal