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Question: For narrating some incidents A speaks truth in \(75\% \) cases and B in \(80\% \) of the cases. In n...

For narrating some incidents A speaks truth in 75%75\% cases and B in 80%80\% of the cases. In narrating some cases both A and B are likely to contradict each other. What is the percentage of the cases in which they both likely contradict each other, narrating the same incident?
(A) 25%25\%
(B) 40%40\%
(C) 35%35\%
(D) 10%10\%

Explanation

Solution

In this we apply the probability of happening an event and not happening of that particular event. So, the probability of A speaking truth is P (A) = 75%75\% or 34\dfrac{3}{4}and not speaking truth or lie P(A)P(\overline A ) = 25%25\% or14\dfrac{1}{4}. Similarly the probability of B speaking truth is P (B) = 80%80\% or 45\dfrac{4}{5}and not speaking truth is P(B)P(\overline {B)} = 20%20\% or15\dfrac{1}{5}. In case of contradiction with each other is when A speaks truth and B speaks lie or A speaks lie and B speaks truth. For finding the probability we add both the situation and find the percentage.

Complete step-by-step answer:
Let A be Event that speaks the truth and B be Event that speaks the truth
So, the probability of A speaking truth P(A)= 75%75\%
=75100=34\dfrac{{75}}{{100}} = \dfrac{3}{4}
The probability of B speaking truth P(B)= 80%80\%
=80100=45\dfrac{{80}}{{100}} = \dfrac{4}{5}
We know P(A)+P(A)=1P(A)+P(\overline A )=1 Hence,
Probability of A not speaking truth P(A)P(\overline A )= 134=141 - \dfrac{3}{4} = \dfrac{1}{4}
Probability of B not speaking truth P(B)P(\overline {B)} = 145=151 - \dfrac{4}{5}=\dfrac{1}{5}
Now, A and B contradict each other=[A speaks truth and B speaks lie] or [A speaks lie and B speaks truth]
We will add both situation
= P(A)×P(B)+P(A)×P(B)P(A) \times P(\overline B ) + P(\overline A ) \times P(B)
=(34×15)+(14×45)(\dfrac{3}{4} \times \dfrac{1}{5}) + (\dfrac{1}{4} \times \dfrac{4}{5})
=320+420\dfrac{3}{{20}} + \dfrac{4}{{20}}
=720\dfrac{7}{{20}}
For percentage we multiply 720\dfrac{7}{{20}} by 100%100\%
=(720×100)%(\dfrac{7}{{20}} \times 100)\%
=35%35\%
So, the case when A and B contradicts is 35%35\% .
The correct answer is C=35%35\% .

So, the correct answer is “Option C”.

Note: When there is a case of contradiction we must consider both the cases i.e. probability of happening of the event and probability not happening of the event. The probability of the event lies between 0 and 1, where 0 and 1 are included.