Question

For n ∈ $\N$, if
$a_n=\frac{1}{n^3+1}+\frac{2^2}{n^3+2}+...+\frac{n^2}{n^3+n}$
then the sequence \left\\{a_n\right\\}_{n=1}^{\infin} converges to ____________ (rounded off to two decimal places)

Answer 1

The correct answer is 0.30 to 0.40. (approx)