Question

For $n \in N$, let S _{ n }=\left\\{ z \in C :| z -3+2 i |=\frac{ n }{4}\right\\} and T_n=\left\\{z \in C:|z-2+3 i|=\frac{1}{n}\right\\} Then the number of elements in the set \left\\{ n \in N : S _{ n } \cap T _{ n }=\phi\right\\} is :

• A. 0
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (D)

4

Answer 2

Therefore, the correct option is (D): 4