Question

For, $N{H_{\text{4}}}Cl\left( s \right) + {H_2}O \to N{H_4}Cl\left( {aq} \right);$ $\Delta H = 16.3kJ$ .
In the above reaction, $\Delta H$ represents:
A) Heat of solution
B) Integral heat of solution
C) Heat of dilution
D) Heat of ionization

Answer 1

We need to remember that the enthalpy is a property of a thermodynamic framework, characterized as the amount of the frameworks inside energy and the result of its pressing factor and volume. It is a helpful state work normally utilized in numerous estimations in substance, organic, and actual frameworks at a consistent pressing factor. The pressing factor volume term communicates the work needed to set up the framework's actual measurements, for example to account for it by uprooting its surroundings. As a state work, enthalpy relies just upon the last design of interior energy, pressing factor, and volume, not on the way taken to accomplish it. The unit of estimation for enthalpy in the International System of Units (SI) is the joule.

Complete step by step answer:
We must need to know that the total enthalpy can't be estimated straightforwardly on the grounds that the inner energy contains segments that are obscure, not effectively open, or are not of interest in thermodynamics. Practically speaking, an adjustment in enthalpy $\Delta H$ is the favored articulation for estimations at consistent pressing factors, since it streamlines the depiction of energy move. At the point when matter exchange into or out of the framework is likewise forestalled, the enthalpy change approaches the energy traded with the climate by heat. Alignment of enthalpy changes requires a reference point.
The amount of heat released or absorbed at the time when the reaction is carried out at constant pressure is called heat of solution.
The given reaction is,
$N{H_{\text{4}}}Cl\left( s \right) + {H_2}O \to N{H_4}Cl\left( {aq} \right);$ $\Delta H = 16.3kJ$
Here, $\Delta H$ represents the heat of solution. Thus option A is correct.

Note:
We must remember that the enthalpies for synthetic substances at a consistent pressing factor typically allude to standard state: most normally 1 bar $\left( {100kPa} \right)$ pressure. Standard state doesn't carefully determine a temperature, yet articulations for enthalpy for the most part reference the standard warmth of development at $25^\circ C\left( {298K} \right)$ For endothermic the change $\Delta H$ is a positive worth; for exothermic is negative.