For (N^{3-} >O^{2-}>F^{-} and Na^{+},) the order in which th... | Chemistry | SolveeIt

Question

For $N^{3-} >O^{2-}>F^{-} and Na^{+},$ the order in which their ionic radii varies is

$N^{3-}>O^{2-}>F->Na^{+}$

$N^{2-}>Na^{+}>O^{2-}>F-$

$Na^{+}>O^{2-}>N^{3-}>F-$

$O^{2-}>F->Na^{+}>N^{3-}$

Answer

$N^{3-}>O^{2-}>F->Na^{+}$

Explanation

Solution

$N^{3-},O^{2-}, F-$ and $Na^{+}$ are all isoelectronic species. As the atomic number increases, nuclear attraction increases, hence the order of ionic radii
$N^{3-}>O^{2-}>F->Na^{+}$

Chemistry Question on Structure of atom

Solution