Question
Question: For MRI, a patient is slowly pushed in a time of 10s within the coils of the magnet where the magnet...
For MRI, a patient is slowly pushed in a time of 10s within the coils of the magnet where the magnetic field is B = 2.0T. If the patient’s trunk is 0.8m in circumference, the induced EMF around the patient’s trunk is:
A) 10.18× 10-2 V
B) 9.66 ×102V
C) 10.18× 10-3 V
D) 1.5×10-2V
Solution
The question is asking about the induced EMF and the concept of induced EMF is given by Faraday’s Law:
E=−dtdϕ (Where ϕ is the flux induced, E is the EMF, t is the time)
Minus sign in the above equation comes from the Lenz law.
Using the above two laws we will conclude the problem.
Complete step by step solution:
Faraday’s law states that: Any change in the magnetic environment of the coil of conductors will cause a voltage (EMF) to be induced in the coil.
E=−dtdϕ
Generally the change in flux takes place or we can say that the rate of change of flux causes induced EMF.
Electric Flux: electric flux is the property of an electric field that may be thought of as the number of electric lines of force that intersect at a given point.
Let’s calculate the EMF induced:
We have: E=−dtdϕ
We can write ϕ = BA ( B is the magnetic field and A is the area).
∴E=−AdtdB................1
B = 2Tesla and the circumference of the trunk is given 0.8m.
To calculate the area we must have the radius of the trunk.
Circumference is:
⇒2πr=0.8 ⇒r=2π0.8=0.127m
Radius of the circumference is 0.127m
Now area of the trunk:
⇒πr2=π(0.127)2
⇒πr2=π(0.127)2=.0509m2
We substitute all the values in equation 1
⇒E=−.0509×102 ⇒E=.1019×10−1
⇒E=10.19×10−3 (Multiply the numerator and denominator by 100)
Option 3 is correct.
Note: Lenz law which we have mentioned above states that the direction of the electric current which is induced in a conductor by a changing magnetic field is such that the magnetic field created by the induced current opposes the initial changing magnetic field.