Question
Question: For \(Mn{O_2} + KOH + {O_2}\xrightarrow{\Delta }2{K_2}Mn{O_4} + 4{H_2}O\) If true enter \(1\) else...
For MnO2+KOH+O2Δ2K2MnO4+4H2O
If true enter 1 else 0.
Solution
It is of the +6 oxidation state of the permanganate ion. In a strongly basic solution, the permanganate (VII) is reduced to the +6 oxidation state. It produces a green color.
Complete step by step answer:
In compounds, manganese remains with a number of different oxidation states. It can be easily raised to the +2 state. For example, by reaction with hydrochloric acid (HCl) to form manganous chloride, MnCl2. Manganese can also be found in the +3 (manganic) oxidation state. But this oxidation state is unstable. It usually goes back to the +2 oxidation state. Both of these manganous and manganic ions can form acidic solutions. Manganese is actually found largely in the +4 oxidation state in manganese dioxide (MnO2). The +4 oxidation state is amphoteric, which means in the +4 oxidation state manganese can either donate or accept electrons in any chemical reactions. Manganese also exists in +6 and +7 oxidation states. The +6 oxidation state is found largely in the manganate ion (MnO4−) and the +7 oxidation state is found largely in the permanganate ion (MnO4−). These two ions are stable in basic solutions.
In a strongly basic solution, we can also see that the permanganate (VII) is reduced to the (green) +6 oxidation state of the manganate ion (MnO24−):
MnO4−+e−→MnO24−
Here, KOH is the basic medium. So, when MnO2 reacts with KOH in the presence of O2, potassium permanganate (K2MnO4) (green colored) is obtained. The required reaction is:
2MnO2+4KOH+O2→2K2MnO4+2H2O
So, it is true.
Note: Manganese can be found in abundance in nature. We should remember that manganese can also be found in +1 oxidation state (in the case of complex cyanide). Also, we should remember that manganese is not very stable in its +5 oxidation state in basic solution.