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Question: For iron it's density is 7500 kg/m<sup>3</sup> and mass 0.075 kg. If it's magnetic moment is 8 × 10<...

For iron it's density is 7500 kg/m3 and mass 0.075 kg. If it's magnetic moment is 8 × 10–7Amp×m2, it's intensity of magnetization is

A

8 Amp/m

B

0.8 Amp/m

C

0.08 Amp/m

D

0.008 Amp/m

Answer

0.08 Amp/m

Explanation

Solution

I=MV=Mdm=8×10−7×75000.075=0.08Amp/m\mathrm { I } = \frac { \mathrm { M } } { \mathrm { V } } = \frac { \mathrm { Md } } { \mathrm { m } } = \frac { 8 \times 10 ^ { - 7 } \times 7500 } { 0.075 } = 0.08 \mathrm { Amp } / \mathrm { m }