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Question

Chemistry Question on Electrochemistry

For hydrogen - oxygen fuel cell at one atmatm and 298K298\, K H2(g)+12O2(g)H2O(l);ΔG=240kJH_2(g)+\frac {1}{2} O_2(g) \to H_2O_{(l)} ; \Delta G^\circ=-240\, kJ EE^\circ for the cell is approximately, (Given F=96,500CF \,= \,96,500 \,C)

A

1.25V1.25 \,V

B

1.26V1.26 \,V

C

2.48V2.48\, V

D

2.5V2.5\, V

Answer

1.25V1.25 \,V

Explanation

Solution

From ΔG=nFE\Delta G^{\circ}=-n F E^{\circ}

where, n=n= number of moles of electrons

transferred =2=2
F=96500C\Rightarrow F=96500\, C
ΔG=240kJ=240×1000J\Delta G^{\circ}=-240\, kJ =-240 \times 1000\, J
E=2400002×96500=1.24V\therefore E^{\circ}=\frac{-240000}{-2 \times 96500}=1.24\, V