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Question

Chemistry Question on Electrochemistry

For how long 2.5 ampere of current is passed to supply 54000 C of charge ?

A

1 hr

B

2.5 hr

C

6 hr

D

9 hr

Answer

6 hr

Explanation

Solution

Q=ItQ = It t=QIt = \frac{Q}{I} =540002.5amp = \frac{54000}{2.5\,amp} =21600sec= 21600\,sec =2160060×60 = \frac{21600}{60\times 60} hours =6= 6 hours