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Question: For \(f\left( x \right)=-4x\) how do you find \(f\left( -1 \right)\) ?...

For f(x)=4xf\left( x \right)=-4x how do you find f(1)f\left( -1 \right) ?

Explanation

Solution

It is given that for any value of x the function is defined by, f(x)=4xf\left( x \right)=-4x . Finding f(1)f\left( -1 \right) means find the solution of the function for which the value of x is given which is 1-1. Therefore substitute the value of x which is 1-1 in the function, and then evaluate. The result which we are going to get will be f(1)f\left( -1 \right).

Complete step by step solution:
The given expression or function is f(x)=4xf\left( x \right)=-4x
This function means that for any value of x belonging to a real number, the function defined is f(x)=4xf\left( x \right)=-4x.
Here a function also says that every input x that we give has exactly one output.
In the question, they have asked us to find f(1)f\left( -1 \right)
So here the value of x is given. It is 1-1 .
Hence to find f(1)f\left( -1 \right) we shall substitute the value of x which is 1-1 in the function.
On substituting the value in the given function, we get,
f(1)=4(1)\Rightarrow f\left( -1 \right)=-4(-1)
Which on evaluating we get,
f(1)=+4\Rightarrow f\left( -1 \right)=+4

Hence given that the function, f(x)=4xf\left( x \right)=-4x then f(1)f\left( -1 \right) is equal to 44 .

Note: The function defines a property or a relation between the input and the output such that each input relates to exactly one output. This means that if the object xx is in the set of inputs (called the domain) then a function ff will map the object xx to exactly one object f(x)f\left( x \right) in the set of possible outputs (called the codomain). One should be careful while substituting the values in the expression. Whenever a function f(x)f(x) is given and we have to find the value of f(p)f(p), just substitute the value of ppin place of xxin the function to get f(p)f(p).