Question

For definite length of wire, if the weight used for applying tension is immersed in water, then frequency will –

• A. Become less
• B. Become more
• C. Remain equal
• D. Become zero

Answer 1

Answer: (A)

Become less

Answer 2

For stretched string

n µ $\sqrt{T}$ µ $\sqrt{M.g}$

When weight is dipped in water due to buoyancy force, tension decreases and hence frequency decreases