Question: For decolourisation of 1 mole of acidified $KMnO_{4}$the moles of $H_{2}O_{2}$required are....

Question

For decolourisation of 1 mole of acidified $KMnO_{4}$ the moles of $H_{2}O_{2}$ required are.

Answer 1

: $2KNnO_{4} + 3H_{2}SO_{4} \rightarrow K_{2}SO_{4} + 2MnSO_{4} + 3H_{2}O$

$+ 5\lbrack O\rbrack\left\lbrack H_{2}O_{2} + O \rightarrow H_{2}O + O_{2} \right\rbrack \times 5$

Hence, 1 mole of $KMnO_{4}$ requires 5/2 moles of $H_{2}O_{2}$

Question: For decolourisation of 1 mole of acidified \(KMnO_{4}\)the moles of \(H_{2}O_{2}\)required are....