Question

For decolourisation of $1$ mole of acidified $KMnO_4$ the moles of $H_2O_2$ required are

• A. $1/2$
• B. $3/2$
• C. $5/2$
• D. $7/2$

Answer 1

Answer: (C)

$5/2$

Answer 2

$H _{2} O _{2}$ reduces acidified $KMnO _{4}$ to colourless $MnSO _{4}$. $2\, mol$ of $KMnO _{4}$ oxidise $5 \,mol$ of $H _{2} O _{2}$ $\therefore 1 \,mol$ of $KMnO _{4}$ will oxidise $\frac{5}{2} mol$ of $H _{2} O _{2}$.