Question

For $d$-electron, the orbital angular momentum is

• A. $\frac{\sqrt{6h}}{2\pi}$
• B. $\frac{\sqrt{2h}}{2\pi}$
• C. $\frac{h}{2\pi}$
• D. $\frac{2h}{\pi}$

Answer 1

Answer: (A)

$\frac{\sqrt{6h}}{2\pi}$

Answer 2

The angular momentum of an electron in an orbital is given by
$\mu_{1} =\sqrt{l\left(l+1\right)} \frac{h}{2\pi}$
For $d$-orbital, $l = 2$
$\therefore \:\:\:\: \mu_{1} =\sqrt{2\left(2+1\right)} \frac{h}{2\pi} =\sqrt{6} \frac{h}{2\pi}$