Question
Question: For carbanion stability order will be:  , so it will stabilize the carbanion.
-So, from the given structure S will have the least stable carbanion because it doesn't have a nitro or electron-withdrawing group.
-Now, in structure P, the nitro group is at ortho position so it will be the most stable because here resonance is more effective and makes the carbanion stable.
Resonance of structure P:
Resonance structure of R:
-As it is present adjacent to the carbanion so it will have more stability than para-nitro because it will decrease more negative ion on the carbanion and forms the resonance structure:
-Whereas the stability of R will be less than P and Q because the nitro group is present at meta position due to which there is less resonance effect as given below:
Resonance structure of Q:
So, the correct answer is “Option B”.
Note: Electron donating groups such as hydroxyl group, alkyl group makes the carbanion unstable because they tend to donate the pair of an electron to the carbon atom and increases the electron density on the carbanion making it more unstable.