Question
Question: For \(CaC{O_3}(s)\overset {} \leftrightarrows CaO(s) + C{O_2}(g),\,{K_c}\,\)is equal to: A. \(\lef...
For CaCO3(s)⇆CaO(s)+CO2(g),Kcis equal to:
A. [CO2]
B. [CaO]
C.[CaCO3]
D. None of these.
Solution
The equilibrium constant is a ratio of the concentration of the products to the concentration of the reactants. If the K value is less than one the reaction will move to the left and if the K value is greater than one the reaction will move to the right.
Complete step by step answer:
Equilibrium constant Kc, is the ratio of equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.
For a reaction:aA+bBcC+dD
Equilibrium constant: Kc=[A]a[B]b[C]c[D]d
Calculation of Kc:
For the gas phase reaction- The concentrations of gases are corporated in its value. The concentrations of gases are expressed in the formula of equilibrium constant.
For pure solid and liquids: Concentrations of pure solids and liquids are fixed by their density and molar mass (both constants) and do not vary with the amount.
Thus , the concentration of solids and liquids are incorporated in the value of Kc, they are not part of variable expressions.
Solve the given question;
CaCO3(s)CaO(s)+CO2(g)
Write all the values of stoichiometric coefficients ;
a=1, b=0, c=1, d=1;
we know that in the equation part concentration of only gaseous part will be present.
So the equation of Kcwill be equal to Kc=[CO2]
Because the concentration of only gaseous parts will be present in the equation , concentration of solids and liquids would be absent , as we have discussed earlier. Stoichiometric coefficient is 1 . So power is raised to power 1.
So, our final answer would be [CO2] option (A).
Note: Characteristics of Kc:
Equilibrium can be approached from both direction
Kc is independent of initial concentration of reactants and products and also of temperature.