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Question: For \(C{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O + \)Heat if \[5\]mole of methane \((C{H_4})\) react, how ...

For CH4+2O2→CO2+2H2O+C{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O + Heat if 55mole of methane (CH4)(C{H_4}) react, how many mole of oxygen (O2)({O_2}) will be consumed?

Explanation

Solution

The stoichiometry of the reaction gives us an idea about the amount of reactant reacts in a particular ratio of mole or mass or number. By the help of stoichiometry of reaction we can identify the minimum number of moles of reactant required to form products during the reaction.

Complete step by step answer:
During the chemical reaction, we follow the law of conservation of mass.
According to the law, during the chemical reaction, mass remains constant. i.e., mass of the reactant as well as mass of product are the same.
To follow the above law, we balance the chemical reaction in which we balance all the atoms included in the reactant as well as in the product.
A chemical reaction which contains more than one reactant to form a product, both reactants must combine in a definite ratio to form the product. Each and every reactant combines either in a fixed mole ratio or in a mass ratio to form a product.
Given equation: CH4+2O2→CO2+2H2OC{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O
In the above equation, both methane and oxygen combine in a fixed mole ratio of 1:21:2 to form carbon dioxide and water molecules.
The above reaction is balanced according to the Law of conservation of mass, where the mass of the reactant side is equal to the mass of the product side. According to the reaction, one mole of methane combines with two moles of oxygen gas to form one mole of carbon dioxide and two mole of water.
In the given question, 55 mole of methane gas is given
So according to the stoichiometry of the reaction
11 mole of methane gas combines with 22 mole of oxygen gas
So, 55 mole of methane gas combines with 1010 mole of oxygen gas
Final answer:
The final answer is 1010 moles of oxygen gas is consumed by 55 mole of methane gas.

Note:
In every reaction, atom conservation is very important and in any chemical reaction every time conservation of atom is there, by the help of atom conservation we can balance any chemical reaction.