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Question: For any four points P, Q, R, S, \(\left| \overset{\rightarrow}{PQ} \times \overset{\rightarrow}{RS}...

For any four points P, Q, R, S,

PQ×RSQR×PS+RP×QS\left| \overset{\rightarrow}{PQ} \times \overset{\rightarrow}{RS}–\overset{\rightarrow}{QR} \times \overset{\rightarrow}{PS} + \overset{\rightarrow}{RP} \times \overset{\rightarrow}{QS} \right|is equal to

4 times the area of the triangle –

A

PQR

B

QRS

C

PRS

D

PQS

Answer

QRS

Explanation

Solution

PQ\overset{\rightarrow}{PQ}× RS\overset{\rightarrow}{RS}QR\overset{\rightarrow}{QR} × PS\overset{\rightarrow}{PS} + RP\overset{\rightarrow}{RP} × QS\overset{\rightarrow}{QS}

= (PS\overset{\rightarrow}{PS}+ SQ\overset{\rightarrow}{SQ}) ×RS\overset{\rightarrow}{RS}QR\overset{\rightarrow}{QR}× PS\overset{\rightarrow}{PS} + (RS\overset{\rightarrow}{RS} + SP\overset{\rightarrow}{SP} ) × QS\overset{\rightarrow}{QS}

= PS\overset{\rightarrow}{PS} × (RS\overset{\rightarrow}{RS}+SQS\overset{\rightarrow}{Q} + QR\overset{\rightarrow}{QR}) – SQ\overset{\rightarrow}{SQ}× SR\overset{\rightarrow}{SR}SQ\overset{\rightarrow}{SQ}× SR\overset{\rightarrow}{SR}

= PS\overset{\rightarrow}{PS} ×0\overset{\rightarrow}{0} – 2 SQ\overset{\rightarrow}{SQ} × SR\overset{\rightarrow}{SR} = 4 × area of DQRS