QuestionReportQuestion: For any event A...For any event AAP(A)+P(Aˉ)=0P ( A ) + P ( \bar { A } ) = 0P(A)+P(Aˉ)=0BP(A)+P(Aˉ)=1P ( A ) + P ( \bar { A } ) = 1P(A)+P(Aˉ)=1CP(A)>1P ( A ) > 1P(A)>1DP(Aˉ)<1P ( \bar { A } ) < 1P(Aˉ)<1AnswerP(A)+P(Aˉ)=1P ( A ) + P ( \bar { A } ) = 1P(A)+P(Aˉ)=1ExplanationSolutionIt is obvious.