Solveeit Logo

Question

Question: For any event A...

For any event A

A

P(A)+P(Aˉ)=0P ( A ) + P ( \bar { A } ) = 0

B

P(A)+P(Aˉ)=1P ( A ) + P ( \bar { A } ) = 1

C

P(A)>1P ( A ) > 1

D

P(Aˉ)<1P ( \bar { A } ) < 1

Answer

P(A)+P(Aˉ)=1P ( A ) + P ( \bar { A } ) = 1

Explanation

Solution

It is obvious.