Question
Question: For an RLC circuit, driven with voltage of amplitude \(vm\) and frequency \({\omega _0} = \dfrac{1}{...
For an RLC circuit, driven with voltage of amplitude vm and frequency ω0=LC1 the current exhibits resonance. The quality factor, Q is given by
a) (ω0C)R
b) ω0CR
c) Rω0L
d) Lω0R
Solution
The quality factor is defined as the voltage magnification of the circuit at resonance. Electrical resonance occurs in an electric circuit at a particular resonant frequency when the impedances or admittances of circuit elements cancel each other.
Complete step by step answer:
Let’s define all the data given in the question:
Voltage amplitude =vm
Frequency, ω0=LC1
It is given that the current exhibits resonance.
Thus frequency ω0when subjected to resonance:
\Rightarrow {\omega _0} = \dfrac{1}{{\sqrt {LC} }}\left\\{ {{X_L} = {X_C}} \right\\}
We need to find the quality factor, Q
The goodness or quality of a resonant circuit is described by the term quality factor, Q of a resonant circuit. If the figure is a higher value that corresponds to a narrower bandwidth.
The quality factor, Q is given by, Q=Bwω0
Where, Bw=Band width,
We know the value of bandwidth by the formula,
Bw=LR
Applying this value of band width to the formula of the quality factor, we get,
⇒Q=Bwω0
⇒Q=Rω0L
From The above equation, we get the value for the quality factor, that is,
The quality factor, Q=Rω0L
So the final answer will be Option(C).
Note: A resonant L-C-R circuit’s sharpness of resonance can be determined by the ratio of resonant frequency with the selectivity of the circuit. And this ratio is called the Quality Factor or the Q-factor. The goodness or quality of a resonant circuit is described by the term quality factor, Q of a resonant circuit. If the figure is a higher value that corresponds to a narrower bandwidth, which is desirable in many applications. More formally, Q is the ratio of power stored to power dissipated in the circuit.