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Question

Physics Question on thermal properties of matter

For an object radiating heat at 300 K, the wavelength corresponding to maximum intensity is λ\lambda. If the temperature of body is increased by 300 K, the new wavelength corresponding to maximum intensity will be

A

λ2\frac{\lambda}{2}

B

2λ{2\lambda}

C

λ{\lambda}

D

5λ2\frac{5\lambda}{2}

Answer

λ2\frac{\lambda}{2}

Explanation

Solution

According to the Wein’s displacement law, the wavelength of the maximum intensity (λ) of radiation is directly proportional to absolute temperature (T). i.e
λ ∝ 1T\frac{1}{T} ⇒ λT= constant
⇒ λ1T1 = λ2T2
Given, for T1 = 300 K, λ1 = λ
Now, if the temperature of the body is increased by 300 K, then final temperature of the body will be
T2 = 300 +300 = 600 K
Therefore, the new wavelength corresponding to maximum intensity will be,
λ2 = λ1T1T2\frac{\lambda_1T_1}{T_2} = λ300600\frac{\lambda*300}{600} = λ2\frac{\lambda}{2}
Answer. A