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Question: For an isothermal reversible expansion process, the value of q can be calculated by the expression...

For an isothermal reversible expansion process, the value of q can be calculated by the expression

A

q=2.30nRTlog⁡V2V1q = 2.30nRT\log\frac{V_{2}}{V_{1}}

B

q=−2.303nRTlog⁡V2V1q = - 2.303nRT\log\frac{V_{2}}{V_{1}}

C

q=−2.303nRTlog⁡V1V2q = - 2.303nRT\log\frac{V_{1}}{V_{2}}

D

q=−Plog⁡V1V2exp⁡q = - {P\log\frac{V_{1}}{V_{2}}}_{\exp}

Answer

q=2.30nRTlog⁡V2V1q = 2.30nRT\log\frac{V_{2}}{V_{1}}

Explanation

Solution

: q=−W=2.303nRTlog⁡V2V1q = - W = 2.303nRT\log\frac{V_{2}}{V_{1}}