Question
Question: For an ideal gas of diatomic molecules...
For an ideal gas of diatomic molecules
A
Cp=25R
B
Cv=23R
C
CP−Cv=2R
D
CP=27R
Answer
CP=27R
Explanation
Solution
CP=(2f+1)R=(25+1)R=27R
For an ideal gas of diatomic molecules
Cp=25R
Cv=23R
CP−Cv=2R
CP=27R
CP=27R
CP=(2f+1)R=(25+1)R=27R