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Question

Question: For an ideal gas of diatomic molecules...

For an ideal gas of diatomic molecules

A

Cp=52RC_{p} = \frac{5}{2}R

B

Cv=32RC_{v} = \frac{3}{2}R

C

CPCv=2RC_{P} - C_{v} = 2R

D

CP=72RC_{P} = \frac{7}{2}R

Answer

CP=72RC_{P} = \frac{7}{2}R

Explanation

Solution

CP=(f2+1)R=(52+1)R=72RC_{P} = \left( \frac{f}{2} + 1 \right)R = \left( \frac{5}{2} + 1 \right)R = \frac{7}{2}R