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Question

Physics Question on Thermodynamics

For an ideal gas

A

the change in internal energy in a constant pressure process from temperature T1T_1, to T2T_2 is equal to nCv(T2T1)nC_v (T_2-T_1), where Cv_v is the molar heat capacity at constant volume and n the number of moles of the gas

B

the change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process

C

the internal energy does not change in an isothermal process

D

no heat is added or removed in an adiabatic process

Answer

no heat is added or removed in an adiabatic process

Explanation

Solution

ΔU\Delta U = nCv_v Δ\DeltaT = nCv_v (T2t1)_2-t_1) in all processes

Δ\therefore \, \, \, \, \, \, \, \DeltaU = Δ-\DeltaW or | Δ\Delta U| = | Δ\Delta W |
(c) In isothermal process Δ\DeltaT = 0
Δ\therefore \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \DeltaU= 0 (asΔU=nCvΔT) \, \, \, \, \, \, \, \, \, \, \, (as \Delta U =nC_v \Delta T )
(d) In adiabatic process Δ\DeltaQ = 0
\therefore \, \, All the options are correct.