Question
Question: For an elementary reaction, \(X(g)\to Y(g)+Z(g)\), the half life period is 10 min. In what period of...
For an elementary reaction, X(g)→Y(g)+Z(g), the half life period is 10 min. In what period of time would concentration of X be reduced to 10% of original concentration?
(a)- 20 min
(b)- 33 min
(c)- 15 min
(d)- 25 min
Solution
The given reaction is X(g)→Y(g)+Z(g), so the rate of the reaction will be:
Rate=k[X]
So, it following the first-order kinetics, then find the rate constant by using the formula:
t1/2=k0.693
Then to find the time of the completion of the reaction at specific concentration, use the formula:
k=t2.303loga−xa
Where a is the initial concentration of the reactant and a-x is the final concentration of the reactant.
Complete answer:
In the question given above, we know the half life of the reaction is 10 min, and the given reaction is:
X(g)→Y(g)+Z(g)
In this reaction only one reactant is present so, we write the rate of the reaction as:
Rate=k[X]
From this, we can see that this reaction will follow the first-order kinetics, and we can find the rate constant of the reaction by using the half-life of the reaction by using the formula:
t1/2=k0.693
Putting, the value we can write:
10=k0.693
k=100.693=0.0693
The k will be 0.0693
Now, to find the time of the completion of the reaction at specific concentration, i.e., at 10%, we can use the formula:
k=t2.303loga−xa
Where a is the initial concentration of the reactant and a-x is the final concentration of the reactant.
So, a will be 100 and a – x will be 10, putting the values we get:
t=k2.303loga−xa
t=0.06932.303log10100
t=0.06932.303log10
t=33.23
So, the time taken will be 33.23 min, and from the options, it is near to the 33 value.
Therefore, the correct answer is an option (b)- 33 min.
Note:
From the reactants, in the reaction, we can find the order of the reaction, when the value is not given. Half-life time is the time of the reaction when the concentration of the reactant becomes half of the initial concentration.