Question

For an electron, with n = 3 has only one radial node. The orbital angular momentum of the electron will be

• A. 0
• B. $\sqrt{6}\frac{h}{2\pi}$
• C. $\sqrt{2}\frac{h}{2\pi}$
• D. $3\left( \frac{h}{2\pi} \right)$

Answer 1

Answer: (C)

$\sqrt{2}\frac{h}{2\pi}$

Answer 2

Number of radial nodes = n – $\ell$– 1 = 1, n = 3.

$\therefore$ $\ell$ = 1.

Orbital angular momentum $= \sqrt{\mathcal{l}\left( \mathcal{l} + 1 \right)}\frac{h}{2\pi} = \sqrt{2}\frac{h}{2\pi}.$