Question

For an electron and a proton (mp=1847 me) with same de-broglie wavelength, the ratio of linear momentum is equal to?

• A. 1:2
• B. 2:1847
• C. 1:1
• D. $\sqrt{1847}{1}$

Answer 1

Answer: (C)

1:1

Answer 2

The correct option is (C): 1:1
$\lambda=\frac{h}{p}$
As $p_{1} = p_{2}$
$\lambda_{1}=\lambda_{2}$