Question

For an adiabatic reversible expansion of a perfect gas DP/P is equal to

• A. $\frac{\Delta V}{V}$
• B. g$\frac{\Delta V}{V}$
• C. – g$\frac{\Delta V}{V}$
• D. – g²$\frac{\Delta V}{V}$

Answer 1

Answer: (C)

– g$\frac{\Delta V}{V}$

Answer 2

PV^g = K

g PV^g–1 dP + V^g dP = O

or – g PV^{g – 1} dV = V^g dP

or – g $\frac{dV}{V}$ = $\frac{dP}{P}$