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Question

Physics Question on Moving Charges and Magnetism

For adjoining fig.,The magnetic field at point, 'P' will be:

 magnetic field at point P

A

μ04πΘ\frac {μ_0}{4\pi}Θ

B

μ0π\frac {μ_0}{\pi}⊗

C

μ02π\frac {μ_0}{2\pi}⊗

D

μ02πΘ\frac {μ_0}{2\pi}Θ

Answer

μ02π\frac {μ_0}{2\pi}⊗

Explanation

Solution

Magnetic field due to 5A5μ02π×2.5=2µ02πMagnetic\ field\ due\ to\ 5A→ \frac {5μ_0}{2\pi×2.5} = \frac {2µ_0}{2\pi}⊗

Magnetic field due to 2.5A2.5μ02π×2.5=µ02πΘMagnetic\ field\ due\ to\ 2.5A→ \frac {2.5μ_0}{2\pi×2.5} = \frac {µ_0}{2\pi}Θ

Resultant Magnetic field=2μ02πµ02π=µ02πResultant \ Magnetic\ field=\frac {2μ_0}{2\pi}-\frac {µ_0}{2π}=\frac {µ_0}{2π}⊗

So, the correct option is (C): μ02π\frac {μ_0}{2\pi}⊗