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Question

Chemistry Question on Chemical Kinetics

For a zero order reaction, AP,t1/2A \longrightarrow P, t_{1 / 2} is (k is rate constant)

A

[A]02k\frac{{{[A]}_{0}}}{2k}

B

In2k\frac{\text{In}\,2}{k}

C

1k[A]0\frac{1}{k{{[A]}_{0}}}

D

In2[A]0k\frac{\text{In}\,2}{{{[A]}_{0}}k}

Answer

[A]02k\frac{{{[A]}_{0}}}{2k}

Explanation

Solution

For zero order reaction, Rate constant k=[A]0[A]ttk=\frac{[A]_{0}-[A]_{t}}{t} Here, A0=A_{0}= initial concentration of reactant At=A_{t}= concentration of reactant after t time. If half-life period is t1/2t_{1 / 2}. Initial amount (A0)\left(A_{0}\right) will become half. At=[A]02A_{t}=\frac{[A]_{0}}{2} k=[A]012[A]0t1/2k=\frac{[A]_{0}-\frac{1}{2}[A]_{0}}{t_{1 / 2}} t1/2=02k\because t_{1 / 2}=\frac{0}{2 k}