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Question

Physics Question on Electric charges and fields

For a uniformly charged ring of radius RR, the electric field on its axis has the largest magnitude at a distance hh from its centre. Then value of hh is :

A

R5\frac{R}{\sqrt{5}}

B

RR

C

R2\frac{R}{\sqrt{2}}

D

R2R \sqrt{2}

Answer

R2\frac{R}{\sqrt{2}}

Explanation

Solution

Electric field on axis of ring
E=kQh(h2+R2)3/2E = \frac{kQh}{\left(h^{2}+R^{2}\right)^{3/2}}
for maximum electric field
dEdh=0\frac{dE}{dh} = 0
h=R2\Rightarrow h = \frac{R}{\sqrt{2}}