Question
Mathematics Question on Trigonometric Functions
For a triangle ABC, the value of cos2A+cos2B+cos2C is least If its inradius is 3 and incentre is M, then which of the following is NOT correct?
A
area of △ABC is 2273
B
sin2A+sin2B+sin2C=sinA+sinB+sinC
C
perimeter of △ABC is 183
D
MA⋅MB=−18
Answer
area of △ABC is 2273
Explanation
Solution
If cos2A+cos2B+cos2C is minimum then A= B=C=60∘
So △ABC is equilateral
Now in-radias r=3
So in △MBD we have
Tan30∘=BDMD=a/2r=a6
1/3=a1=a=63
Perimeter of △ABC=183
Area of △ABC=43a2=273