Solveeit Logo

Question

Physics Question on Electromagnetic waves

For a transparent medium relative permeability and permittivity, μr\mu_ r and ϵr\epsilon_{r} are 1.01.0 and 1.441.44 respectively. The velocity of light in this medium would be,

A

2.5 × 108^8 m/s

B

3 × 108^8 m/s

C

2.08 × 108^8 m/s

D

4.32 × 108^8 m/s

Answer

2.5 × 108^8 m/s

Explanation

Solution

v=1μϵ v = \frac{1}{\sqrt{\mu \epsilon}}
=1μrϵrμ0ϵ0= \frac{1}{\sqrt{\mu_{r} \epsilon_{r} \mu_{0} \epsilon_{0}}}
=3×1081.44= \frac{3\times10^{8}}{\sqrt{1.44}}
=3012×108= \frac{30}{12} \times 10^{8}
=2.5×108ms1= 2.5 \times10^{8} ms^{-1}